Bila fungsi y = 2x² + 6x - m mempunyai nilai minimum 3 maka tentukan m.

Kelas 10 Matematika
Bab Fungsi Kuadrat

y = 2x² + 6x - m
a = 2; b = 6: c = -m

Sumbu simetri
= -b/2a
= -6/(2 . 2)
= -3/2

y = 3
2 . (-3/2)² + 6 . (-3/2) - m = 3
2 . 9/4 - 9 - m = 3

◎◎ dikali 2 ◎◎

9 - 18 - 2m = 6
-2m = 6 + 9
m = 15/-2
m = -15/2
m = -7 1/2