Matematika

Pertanyaan

please help.
160+40+10+...=....
a.160
b.213
c.213 1/3
d.480
e.640

1 Jawaban

  • Deret tak hingga,
    a = 160
    r = 1/4
    [tex]\displaystyle S_\infty=\frac{a}{1-r}=\frac{160}{1-\frac{1}{4}}=\frac{160}{^3/_4} \\ S_\infty=160\times \frac{4}{3}=\frac{640}{3}=213\frac{1}{3}[/tex]

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