Akar 72 × 2 akar 3 : akar 6

4√18 - √72
= 4√(9 x 2) - √(36 x 2)
= 12√2 - 6√2
= 6√2

[tex] \sqrt{72} \times 2 \sqrt{3} \div \sqrt{6} \\ = \sqrt{72} \times \sqrt{12} \div \sqrt{6} \\ = \sqrt{72 \times 2} \\ = \sqrt{36} \\ = 6[/tex]
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