Hitunglah pH dari Campuran 100ml garam CH3COONa 0,1M dengan 50mL Ch3COOH 0,2M

n CH3COOH = 1 * 0.5 = 0.5
n CH3COONa = 0.5 * 0.2 = 0.1

[H+] = Ka * na/nbk = 1.8 x 10^-5 * 0.5/0.2 =1.8 x 10^-5 * 5 
= 9 x 10^-5
pH = - log [H+]
= - log ( 9 x 10^-5)
= 5 - log 9

[OH-] = √(Kw/Ka) x M
= √(10^-14/10^-5) x 0,1
= √10^-10
= 10^-5
pOH = 5
pH = 9


maaf kalau salah ya,,,,