simpangan baku dari data 5,8,2,6,3,6 adalah..

[tex]X= \frac{2+3+5+6+6+8}{6}=5 [/tex]

[tex]S= \sqrt{ \frac{(2-5)^2+(3-5)^2+(5-5)^2+(6-5)^2+(6-5)^2+(8-5)^2}{6} } [/tex]

[tex]S= \sqrt{ \frac{(-3)^2+(-2)^2+0^2+1^2+1^2+3^2}{6} } [/tex]

[tex]S= \sqrt{ \frac{(9+4+0+1+1+9)}{6} }=\sqrt{\frac{24}{6} } = \sqrt {4} = 2 [/tex]