f(x)=3×-5dan g(x)=xpangkat dua-6x,maka rumus(fog)(x)

f(x) =3x-5 , g(x)=x²-6x

fog(x) =f(g(x))
=f(x²-6x)
=3(x²-6x)-5
=3x²-18x-5

Mapel : Matematika

Kelas : 10

Bab : Fungsi Komposisi


→ f(x) = 3x - 5

→ g(x) = x² - 6x

Maka, nilai (f o g) (x) :

(f o g) (x) = f(x² - 6x)

(f o g) (x) = 3(x² - 6x) - 5

(f o g) (x) = 3x² - 18x - 5