tentukan persamaan garis yang melalui (7,2) dan sejajar dengan garis 2x-5y=8 .

m = 2/5
y-y1 = m (x-x1)
y-2 = 2/5 ( x-7)
y-2 = 2/5x - 14/5
y = 2/5x - 14/5 + 10/5
y = 2/5x -4/5

pers garis sejajar m1=m2
m1→ 2x-5y=8
-5y =-2×+8
y= 2/5 + -8/5
m1= 2/5. karena sejajar maka m1=m2= 2/5
per garisnya
y-y1 = m2 ( ×-×1)
y-2 = 2/5 (×-7)
y-2 = 2/5× - 14/5
y= 2/5× - 14/5 +2
y= 2/5 × - 4/5
5y = 2 × - 4
2× -5y - 4 = 0