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Pertanyaan

tolong dibantu y no 5
tolong dibantu y no 5

1 Jawaban

  • 192.168.10.0/25=
    IP Class C
    IP v4 = w.x.y.z
    Net Mask binner = 11111111.11111111.11111111.10000000
    w = 2^8 - 1 = 255
    x = 2^8 - 1 = 255
    y = 2^8 - 1 = 255
    z = (2^8) - (2^7) = 128
    jadi Subnet mask decimal = 255.255.255.128
    Jumlah host / subnet = z = 2^7 -2 = 126
    Jumlah host = z = 128

    192.168.100.0/26=
    IP Class C
    IP v4 = w.x.y.z
    Net Mask binner = 11111111.11111111.11111111.11000000
    w = 2^8 - 1 = 255
    x = 2^8 - 1 = 255
    y = 2^8 - 1 = 255
    z = (2^8) - (2^6) = 192
    jadi Subnet mask decimal = 255.255.255.192
    Jumlah valid host / subnet = z = 2^6 -2 = 62
    Jumlah host
    = 64


    191.200.0.1/17
    IP Class B
    IP v4 = w.x.y.z
    Net Mask binner = 11111111.11111111.10000000.00000000
    w = 2^8 - 1 = 255
    x = 2^8 - 1 = 255
    y = (2^8) - (2^7) = 128
    z = 2^0 - 1 = 0
    jadi Subnet mask decimal = 255.255.128.0
    Jumlah valid host / subnet = 2^15 -2 = 32766
    Jumlah host = 32768