Matematika

Pertanyaan

suatu barisan aritmetika U5=124 dan U9=20 nilai U7 adalah

1 Jawaban

  • U5 = 124
    U5 = a + 4b = 124

    U9 = 20
    U9 = a + 8b = 20

    4b = U9 - U5
    4b = 20 - 124
    4b = -104
    b = -104/4
    b = -26

    a + 4b = 124
    a + 4(-26) = 124
    a + -104 = 124
    a = 124 + 104
    a = 228

    U7 = a + 6b
    = 228 + 6.(-26)
    = 228 - 156
    = 72

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