Dik r1=5 r2=2 d=24 jarak kedua pusat lingkaran adalah

[tex]{d}^{2} = \sqrt{ {p}^{2} - (r1 - r2) {}^{2} } \\ {24}^{2} = \sqrt{ {p}^{2} - (5 - 2) {}^{2} } \\ 576 = \sqrt{ {p}^{2} - 3 ^{2} } \\ 576 = \sqrt{ {p}^{2} - 9} \\ {p}^{2} = \sqrt{576 + 9} \\ {p}^{2} = \sqrt{585} \\ p = 24.18[/tex]

D = 24 : 2 = 12+5+2=19
jadi jaraknya 19 cm