Matematika

Pertanyaan

No. 10 & 11 gmn gan?

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#kasih caranya
No. 10 & 11 gmn gan? #no spam #kasih caranya

1 Jawaban

  • 10. OA = √OP^2 - AP^2
    = √50^2 - 40^2
    = √2500 - 1600
    = √900
    = 30 cm
    Mencari luas segitiga OAP
    L = a × t / 2
    = 30 × 40 /2
    = 1200/2
    = 600 cm^2

    Mencari luas layang2 OAPB
    L = Luas Segitiga OAP × 2
    = 600 × 2
    = 1200 cm^2

    Pencari panjang busur AB
    L = AB × OP / 2
    1200 = AB × 50/2
    1200 = AB × 25
    AB = 1200/25
    AB = 48 cm (d)

    11. D^2 = P^2 - (R+r)^2
    = 13^2 - (3+2)^2
    = 169 - 25
    = 144
    D = √144 (a)