Berapa massa nitrogen pada 25,2 gram HNO3 36 gram CO(NH2)2

Mapel; Kimia
Kelas: X
Materi: Stoikiometri
Kata Kunci: Massa Mollar dan jumlah partikel

Jawab
HNO3
1+14+3×16 = 63
M = 25,2/63
M= 0.4

massa N
massa = 14×0.4
massa = 5.6gram

CO(NH3)2
12+16(14+3)×2
28 + (17×2)
28 + (34)
Mr => 62

M = 36/62 = 0.58
massa N
massa = {12×2} × 0.58
massa = 24×0.58
massa = 14gram