Menggunakan rumus ABC X akar2 - 5X-4 Mohon bantuannya:-)

[tex] {x}^{2} - 5x - 4 = 0 \\ x12 = \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac} }{2a} \\ = \frac{ - ( - 5) \binom{ + }{ - } \sqrt{( { - 5)}^{2} - 4(1)( - 4) } }{2(1) } \\ = \frac{5 \binom{ + }{ - } \sqrt{25 + 16} }{2} \\ = \frac{5 \binom{ + }{ - } \sqrt{41} }{2 } \\ x1 = \frac{5 + \sqrt{41} }{2} \\ x2 = \frac{5 - \sqrt{41} }{2} [/tex]