1.Bentuk sederhana dari √3 / √6-√2 = A. 1/4 (3√2-√6) B. 1/4 (3√2+√6) C. 1/4 (3√2-√6) D.1/8 (3√2+√6) E. 4/12 (3√2-√6) 2. Nilai pangkat 3log 6 - pangkat 3 log 8 +

nomor 1, jawabannya B
[tex] \frac{ \sqrt{3} }{ \sqrt{6} - \sqrt{2} } \times \frac{ \sqrt{6} + \sqrt{2} }{ \sqrt{6} + \sqrt{2} } \\ = \frac{ \sqrt{18} + \sqrt{6} }{6 - 2} \\ = \frac{1}{4} ( 3\sqrt{2} + \sqrt{6})[/tex]
nomor 2, jawabannya C
[tex]3log6 - 3log8 + 3log36 \\ = 3log( \frac{6 \times 36}{8} ) \\ = 3log(27) \\ = 3log {3}^{3} \\ = 3 \times 3log3 \\ = 3 \times 1 = 3[/tex]