siapapun tolon yg soal ini dong yang nomor 3 tolongg

[√2 log 3 × 27 log 125 × 5 log 4√2]/[6 log ½ + 6 log 12]
= [(2^½) log 3 × (3³) log (5³) × 5 log ((2^5)^½)]/[6 log (½ × 12)]
= [(1/½ × 3/3 × 5/2) × 2 log 3 × 3 log 5 × 5 log 2]/[6 log 6]
= [2 × 5/2]/1
= 5