soal limit tolong dibantu ya gaes urgent bgt
Matematika
DanielReward
Pertanyaan
soal limit tolong dibantu ya gaes urgent bgt
1 Jawaban
-
1. Jawaban fawya
1.lim x mendekati 1 (x⁴-2x³+2/2x³+x-3)
Lim x mendekati 1 (4x³-6x²/6x²+1)
=(4-6/6+1)
= -2/7
2.lim x mendekati 1 (√x-1/x⁴-x)
Lim x mendekati 1 (½/4x³-1)
=½/3
=1/6