besok dikumpulkan,tolong dijawab y

[tex]TI = 10 log ( \frac{I}{Io} ) \\ 40 = 10log( \frac{I}{10 ^{ - 14} } ) = 10log(I )- 10log(10 ^{ - 14}) \\ 40 = 10log(I ) + 100 \\ - 10 = log(I ) \\ I = {10}^{ - 10} \\ \\ \frac{I1}{I2} = ( \frac{r1}{r2} )^{2} \\ \frac{{10}^{ - 10}}{I2} = 5 ^{2} \\ I2 = \frac{10 ^{ - 10} }{ 25} = 4 \times 10 ^{ - 12} [/tex]